An insect which can crawl (cannot fly) at a constant speed of 10cm/sec is at a corner 'A' of a room with which has dimensions length is14cm breadth is10cm and height is 12cm. Insect has to go to the diagonally opposite corner 'F' then find the minimum time in which the insect can reach there

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Answer:
Your answer is 2.09secs hope it helps you.
Explanation:
Speed of the insect = 10cm/sec
Then find the face diagonal of the room by the formula=√l^2+b^2+h^2.You will get the answer as 2√110cm=distance the insect had to travel.
By applying speed =Distance /time
&Time=Distance /speed=2√110/10=2.09secs.
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