Math, asked by Praveenchezhian2948, 9 months ago

An inspector is 228 meter behind the thief. The inspectorruns 42 meters and the thief runs 30 meters in a minute. Inwhat time will the inspector catch the thief?

A) 19 minutes B) 20 minutes C) 18 minutes D) 21 minutes

Answers

Answered by neelamgaurav8
0

Inspector s 228 meter behind the thief and now aftersome x distance he will catch the thief. So

x/30 = 228+x/42 => x = 570 m

(228 + 570) / 42 = 19 min

Answered by qgowtam12
0

Answer:

A) 19 minutes

Step-by-step explanation:

Inspector s 228 meter behind the thief and now aftersome x distance he will catch the thief. So

x/30 = 228+x/42 => x = 570 m

(228 + 570) / 42 = 19 min

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