An instantaneous displacement of a simple harmonic oscillator is x = A cos (wt + π/4). Its speed will be maximum at time(a) π/4ω(b) π/2ω(c) π/ω(d) 2π/ω
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Answer:
A) π/4
Explanation:
Instantaneous displacement of a simple harmonic oscillator is x = A cos (wt + π/4
Where, π/4 is initial phase only.
The time interval between zero velocity and half the maximum velocity will be calculated.The velocity is the time derivative of displacement:
v = dy/dt = -Aω(sin ωt + π/4).
Its maximum magnitude equal to Aω is obtained when ωt = π/4, from which t = π/4ω.
So after time interval of π/4w the velocity will drop from maximum velocity to half of the maximum velocity.
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