Physics, asked by toshtushar1250, 1 year ago

An institute uses 20 tubelights of 60 W each, 15 fans of 40 Weach and 2 table lamps of 100 W each for5 hours a day. How many units of electricity are used in the month on April ?(A) 250 kWh(B) 300 kWh(C) 200 kWh(D) 1000 kWh​

Answers

Answered by murtazamannu
3

HEYY DUDE !!

Here us your answer

B) 300 KWH

Attachments:
Answered by Anonymous
10

\Huge{\underline{\underline{\blue{\mathfrak{Answer :}}}}}

\Large{\sf{Given :}}

  • An institution uses 20 tubelights of 60 W each.
  • 15 fans 40 W each.
  • 2 Table lamps 100 W each
  • Time (T) = 5 hrs

\rule{200}{2}

\LARGE{\sf{To \: Find  :}}

Energy consumed in April Month

\rule{200}{2}

\LARGE{\sf{Solution :}}

We have formula :-

\LARGE{\boxed{\boxed{\tt{Energy \: = \: Power \: \times \: Time}}}}

Also Multiple the result by 30 because April have 30 days.

\rule{100}{2}

# Tubelights

Power = 20 × 60

Power = 1200 W ⟹ 1.2 kW

(Now put Value in formula)

Energy = 1.2 * 5 * 30 ⟹ 180 kWh

\Large{\boxed{\red{\sf{Energy \: of \: Tube lights \: = \: 180 \: kWh}}}}

\rule{200}{2}

# Fans

Power = 15 × 40

⟶ Power = 600 W ⟹ 0.6 Wh

(Now put values in formula)

Energy = 0.6 * 5 * 30 ⟹ 90

\Large{\boxed{\red{\sf{Energy \: of \: Fans \: = \: 90 \: kWh}}}}

\rule{200}{2}

# Table Lamps

Power = 2 × 100

⟶ Power = 0.2 Wh

(Now put values in formula)

⟶ Energy = 0.2 * 5 * 30 = 30 kWh

\Large{\boxed{\red{\sf{Energy \: of \: Table \: Lamps\: = \: 30 \: kWh}}}}

\rule{300}{2}

Now Add all the Energy = 90 + 180 + 30

Energy = 300

\Large{\boxed{\orange{\sf{Total \: Energy \: = \: 300 \: kWh}}}}

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