An instruction pipeline was designed with five stages. Individually each of the stages will take 3.2 ns, 2.9ns, 4.1ns, 3.3ns and 3.5ns, respectively. The pipeline latch latency is 0.4ns. What is the minimum cycle time of the pipeline?
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Answer: 4.5 ns
Explanation: confirmed by NPTEL
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The minimum cycle time of the pipeline is 4.5 ns.
Explanation:
Given:-
Time taken by different stages = 3.2ns, 2.9ns, 4.1ns, 3.3ns, 3.5ns
Pipeline latch latency = 0.4ns
To find:-
cycle time
cycle time = maximum of all stages + pipeline latch latency
= 4.1 + 0.4
= 4.5 ns
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