Question

an instrument has 20 division on veriner scale which concide with 19 divisions on the main scale . if one cm on the main scale is divided into 20 parts , findits least count​

Answer 1

▶ Solution :

Given :

▪ An instrument have 20 divisions on vernier scale which concide with 19 divisions on the main scale.

▪ One cm on the main scale is divided into 20 parts.

To Find :

▪ Least count of vernier callipers.

Formula :

✏ Formula of least count of vernier callipers is given by

$\underline{\boxed{\bf{\pink{LC=1MSD-1VSD}}}}$

Calculation :

$\implies\sf\:1MSD=1/20=0.05\:cm\\ \\ \therefore\bf\:1MSD=0.5\:mm\\ \\ \implies\sf\red{20VSD=19MSD}\\ \\ \implies\sf\green{1VSD=\dfrac{19}{20}MSD}\\ \\ \implies\sf\:LC=1MSD-1VSD\\ \\ \implies\sf\:LC=1MSD-\dfrac{19}{20}MSD\\ \\ \implies\sf\:LC=\dfrac{1}{20}\times MSD\\ \\ \implies\boxed{\bf{\orange{LC=0.025\:mm}}}$