An instrument is marked 150 W, 230 V. If the voltage is lowered to 110 V,What will be its power?
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the device is designated by the manufacturer to consume 150W at 230V,
if you lower the voltage (assuming there are connections you can change on the device to do so) you will increase its current draw. P = VI so I = P/V at 230V I = 150/230 or 652 mA. If you lower the voltage to 110V you will have 150/110 or 1364 mA or 1.364A
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