Question

An instrument of resistance 1150 ohm connected to 230 v supply up to 5 minutes find out the current flow through the circuit?

Answer 1

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Heat produced, H = I²Rt

here, $\frac{11_5}{3}$=${I^2_5\:R_5}$ ${→}$ ${I_5}$=$\\sqrt{\frac{10}{5} }$ = √2.

This is the current through resistor 5Ω.

Voltage across resistor 5Ω is ${V_5}$ = ${I_5\:R_5}$

As resistors (4,6) and 5 are in parallel, so potential across (4,6) is equal to ${V_5}$.

As resistor 4 and 6 are in series so current through each resistor ${I_4}$

=${I_6}$

=$\frac{V_5}{4+6}$

= $\frac{5√2}{4+6}$

= $\frac{√2}{2}$

Answer 2

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Heat produced, H = I²Rt

$here, \frac{11_5}{3}$

$={I^2_5\:R_5}$

${→} {I_5}$

$=\begin{gathered}\\sqrt{\frac{10}{5} }\end{gathered}$

= √2.

This is the current through resistor 5Ω.

$Voltage \: across \: resistor \: 5Ω \: is \: {V_5}$

$= {I_5\:R_5}$

As resistors (4,6) and 5 are in parallel, so potential across (4,6) is equal to

${V_5}$

As resistor 4 and 6 are in series so current through each resistor

${I_4}$

$={I_6}$

$=\frac{V_5}{4+6}$

$= \frac{5√2}{4+6}$

$= \frac{√2}{2}$