Question

an insulated Beaker contains 300 gram of water initially at 30 degrees Celsius and water is at 100°C is added until the temperature of the mixture reaches 50°C.

The specific heat capacity of water is 4.2J/(g°C)
How much water is added?
A)60g
B)120g
C)180g
D)750g​

Answer 1

Answer:

Let

(

m

)

g

be the mass of water added.

The heat gained by the water at

30

º

C

=

the heat lost by the water at

100

º

C

.

So,

300

⋅

4.2

⋅

(

50

−

30

)

=

m

⋅

4.2

(

100

−

50

)

300

⋅

20

=

m

⋅

50

m

=

300

⋅

20

50

=

120

g

Answer 2

Answer:

i think

120g is the answer