Question

An insulated box containing a diatomic gas of
molar mass M moving with a speed v, is suddenly
stopped.
The increase in gas temperature as a result of
stopping the box is
(a) zero (b) MINO
3R
(c) Mu?
(d) Mug
2R​

Answer 1

Answer:

∆T=mv^2/3R

Explanation:

Loss in KE=1/2×mn×v^2

If the temperature changes by ∆T then,

5/2×nR∆T=1/2×mnv^2

∆T=mv^2/3R

Answer 2

Answer: ∆T= MV^2/5R

Concept: Thermodynamics

Given: Molar mass M is moving with a velocity V

To Find: The increase in gas temperature as a result of stopping the box

Step-by-step explanation:

Let n represent the number of moles of gas in the container.

The gas's kinetic energy is equal to n(1/2MV^2)              ......... (i)

When the box abruptly stops, this energy is expended in changing the internal energy, which raises the temperature of the gas.

Δ U = nCv Δ T calculates the change in internal energy......... (ii)

for a diatomic gas

Cv = 5/2R

Consequently, we obtain from equations (I) and (ii),

n5R/2 ∆T= n 1/2MV^2

Alternatively, ∆T= MV^2/5R is the preferred option.

Project code: #SPJ2