Question

an insulating pipe of cross section area A contains an electrolyte which has two types of ions their charges being -e and +2e A potential difference applied between the ends of the pipe result in the drifting of the two types of ions having drift speed =V(-ve ion ) and V/4 (+ ion) both ions have same number per unit volume =n the current flowing through the pipe is?​

Answer 1

Answer:

Explanation:

As the number of ions flowing through the pipe is "n". The current(i) flowing through  a pipe is directly proportional to the number of ions(n) , number of electrons(e) flowing through the same, the drift velocity(Vd) of the electrons and the area of cross-section of the pipe(A).

 

Thus, i=neAVd,

Here, i(1)=neAVd and i(2)=n2eAVd/4.

Hence the net current through the pipe is inet = i1 + i2,

inet = neAVd + neAVd/2.

inet = 3/2neAVd.