Question

An insulating rod of length l carries a charge q distributed uniformly on it. The rod is pivoted at an end and is rotated at a frequency f about a fixed perpendicular axis. The magnetic moment of the system is:

Answer 1

Explanation:

Magnetic moment = i*A = q*[2*(pi)*f]*A

A=pi*l^2

mag. mom. =2(pi)^2 q f (l^2)

Answer 2

Answer:

A=pi*l^2 ,1/T=f

Magnetic moment = i*A = q/l*dx*f*pi*x^2

                              = q*[2*(pi)*f]*A

mag. mom. =2(pi)^2 q f (l^2)  

                    =pi*f*l/12