Question

An integer exceed its reciprocal by 143/12 the integer is

Answer 1

$x = \frac{1}{x} + \frac{143}{12} \\ x = \frac{12 + 143x}{12x} \\ 12 {x}^{2} = 12 + 143x \\ 12 {x}^{2} - 143x - 12 = 0 \\ 12 {x}^{2} - 144x + x - 12 = 0 \\ 12x(x - 12) + 1(x - 12) = 0 \\ (x - 12)(12x + 1) = 0 \\ x = 12 \\ x$
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