Question

an integer is chosen at random between 1 and 100 . find the probability that it is (i) divisible by 8 (ii) not divisible by 8

Answer 1

1. 12/100 =3/25..
2. 88/100=22/25..

Answer 2

Hey friend !

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Numbers divisible by 8 between 1 and 100 are 8 ,16 , 24 , 32 , 40 , 48 , 56 , 64 , 72 , 80 , 88 , 96

Outcomes possible for integers divisible by 8 are 12

Probability of getting integers divisible by 8 = possible outcomes / Total number of outcomes.

= 12/100

= 3/25

Probability of getting integers not divisible by 8 = Possible outcomes / Total number of outcomes

= 88/100

= 22/25

# Hope it helps #