an integer is chosen at random between 1 and 100 . find the probability that it is (i) divisible by 8 (ii) not divisible by 8
Answers
Answered by
1
1. 12/100 =3/25..
2. 88/100=22/25..
2. 88/100=22/25..
Answered by
4
Hey friend !
________________________
Numbers divisible by 8 between 1 and 100 are 8 ,16 , 24 , 32 , 40 , 48 , 56 , 64 , 72 , 80 , 88 , 96
Outcomes possible for integers divisible by 8 are 12
Probability of getting integers divisible by 8 = possible outcomes / Total number of outcomes.
= 12/100
= 3/25
Probability of getting integers not divisible by 8 = Possible outcomes / Total number of outcomes
= 88/100
= 22/25
# Hope it helps #
________________________
Numbers divisible by 8 between 1 and 100 are 8 ,16 , 24 , 32 , 40 , 48 , 56 , 64 , 72 , 80 , 88 , 96
Outcomes possible for integers divisible by 8 are 12
Probability of getting integers divisible by 8 = possible outcomes / Total number of outcomes.
= 12/100
= 3/25
Probability of getting integers not divisible by 8 = Possible outcomes / Total number of outcomes
= 88/100
= 22/25
# Hope it helps #
Similar questions