an integer is chosen at random between 1 and 100 .find the probablity that it is
a)divisible 8
b)not divisible 8
Answers
Answered by
10
Heya....!!
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Numbers divisible by 8 between 1 and 100 are 8 ,16 , 24 , 32 , 40 , 48 , 56 , 64 , 72 , 80 , 88 , 96
Outcomes possible for integers divisible by 8 are 12
Probability of getting integers divisible by 8 = possible outcomes / Total number of outcomes.
= 12/100
= 3/25
Probability of getting integers not divisible by 8 = Possible outcomes / Total number of outcomes
= 88/100
= 22/25
# Hope it helps #
________________
Numbers divisible by 8 between 1 and 100 are 8 ,16 , 24 , 32 , 40 , 48 , 56 , 64 , 72 , 80 , 88 , 96
Outcomes possible for integers divisible by 8 are 12
Probability of getting integers divisible by 8 = possible outcomes / Total number of outcomes.
= 12/100
= 3/25
Probability of getting integers not divisible by 8 = Possible outcomes / Total number of outcomes
= 88/100
= 22/25
# Hope it helps #
Answered by
1
1) it is divisible by 8
total outcomes =100
it is divisible by 8=12
12/100 =3/25
2) it is not divisible by 8=
total outcomes =100
not divisible by 8=88
88/100 =22/25
total outcomes =100
it is divisible by 8=12
12/100 =3/25
2) it is not divisible by 8=
total outcomes =100
not divisible by 8=88
88/100 =22/25
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