Question

An integer is chosen at random between 1 and 100 . find the probability that is 1 and 109.find probability that is divisible by 8 and not divisible by 8

Answer 1

the pb of choosing 1=1/100
the pb of 108=0
divisble of 8=8,16,24,32.......96
the pb of divisible of 8=12/100
                                           3/25
the pb of not divisible by 8=88/100
                                                 22/25

Answer 2

Hey, your answer is --

Given, an integer is chosen at random
b/w 1 and 100
so, total number of outcomes = 100

now , probability of getting 1 is
P = 1/100
and probability of getting 109 is
P = 0/100 = 0

now , the possible outcomes that is divisible by 8 is -
8 , 16,24 ,36,40,48,56,64,72,80,88,96
therefore , favorable number of outcomes is 12
so, P(getting divisible by 8) = 12/100
= 3/25

probability of getting number is not divisible by 8 is
P = 100 - 12/100
= 88/100 = 22/25

hope u like