An integer is chosen at random between 1 and 100. Find the probability that it is divisible by 8. Please give the correct answer as per the board answer key as there is a lot of confusion with the total number of outcomes being 100 or 98.
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1) We can find total no. of integer between 1 and 100 that are divisible by 8 by using A.P.
So, Series = 8, 16, 24......96a = 8an = 96d = 8
an = a + (n - 1)d
=> 96 = 8 + (n - 1)8
=> 88/8 = n - 1
=> n = 12
So, possible outcome = 12Total no. of outcome = 98p(getting a no. divisible by 8) = 12/98= 6/49
2) Total no. that are not divisible by 8 between 1 and 100 = 98 - 12 = 86
Possible outcome = 86Total no. of outcome = 98
P(getting no. not divisible by 8) = 86/98
= 43/49
Hope this helps....:)
So, Series = 8, 16, 24......96a = 8an = 96d = 8
an = a + (n - 1)d
=> 96 = 8 + (n - 1)8
=> 88/8 = n - 1
=> n = 12
So, possible outcome = 12Total no. of outcome = 98p(getting a no. divisible by 8) = 12/98= 6/49
2) Total no. that are not divisible by 8 between 1 and 100 = 98 - 12 = 86
Possible outcome = 86Total no. of outcome = 98
P(getting no. not divisible by 8) = 86/98
= 43/49
Hope this helps....:)
EvelynXxX:
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Answered by
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Given:
An integer is chosen between 1 and 100.
Numbers that are divisible by 8 = 8, 16, 24, 32, 40, 48, 56, 64, 72, 80, 88 and 96.
The rest are not divisible by 8.
Calculation:
The integers are 2, 3, 4, 5, 6,..., 99.
The number of possible outcomes = 98 (Excluding 1 and 100)
Therefore,
Sample space, n(S) = 98.
So,
The possibility of the number divisible by 8, n(E) = 12.
To find probability,
By formula,
P(E) = n(E)/n(S)
=12/98
= 6/49
Hence, P(integer divisible by 8) = 6/49
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