An integer is chosen at random between 1 and 100. Find the probability that it is :
(i) divisible by 8.
(ii) not divisible by 8.
Answers
Answered by
2
Total outcomes= 100-1-1 = 98 (since, the numbers are selected between 100 and 1, which means 100 and 1 aren't selected)
Favourable outcomes = 8,16,24,32,40,48,56,64,72,80,88 and 96
P(no. divisible by 8) = 12/98 = 6/49
P( not divisible by 8) = 1-6/49
= 43/49
Favourable outcomes = 8,16,24,32,40,48,56,64,72,80,88 and 96
P(no. divisible by 8) = 12/98 = 6/49
P( not divisible by 8) = 1-6/49
= 43/49
vermaarpit02:
how? can you correct me?
here total outcomes is 100
the numbers are selected BETWEEN 100 and 1 so the numbers selected are 2,3,4,5,6-----99
look here this's saying the nos. between 1-100 so here n (s)=100
you can search this question on Google if you want
yaa
u r correct
no problem ☺️
thanks for the follow
it's all ok
Answered by
1
prob ability of divisible by 8 is 12upon100 that is 0.12
probability of not divisible by 8 is
1-0.12=0.88
that's correct
thanks
bro
are you in 10
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