Question

an integer is chosen at random between 1 to 100 find the probability that it is divisible by 8 and not divisible by 8

Answer 1

In the question it is Given that the numbers are "between 1 and 100", we should exclude both 1 and 100.So we are left with 98 numbers.

i) Total numbers BETWEEN 1 and 100 are 98
Total Number of Outcomes= 98
Number divisible by 8 are : 8,16,24,32,49,48,56,64,72,80,88,96
Number of favourable outcomes = 12
Probability = Number of favourable outcomes / Total number of outcomes
Probability (divisible by 8) = 12/98 = 6/49
P((divisible by 8) = 6/49

ii) Number not divisible by 8 are : 98 -12 = 86
Number of favourable outcomes = 86
Probability = Number of favourable outcomes / Total number of outcomes
Probability (not divisible by 8) = 86/98 = 43/49
P((not divisible by 8) = 43/49

HOPE THIS WILL HELP YOU….

Answer 2

Solution :-

Total number of integers between 1 and 100 = 98 

It s given in the question that an integer is chosen between 1 and 100. So, 1 and 100 are excluded.

So, total number of outcomes are 98

Numbers which are divisible by 8 out of these 98 integers = 8, 16, 24, 32, 40, 48, 56, 64, 72, 80, 88, 96

= 12 numbers are divisible by 8 

So, total number of favourable outcomes are 12

1) Probability (Numbers divisible by 8) = Total number of favourable outcomes/ Total number of outcomes

= 12/98

= 6/49

Numbers which are not divisible by 8 = 98 - 12 

= 86

In this case, total number of favourable outcomes are 86

2) Probability (Numbers not divisible by 8) = 86/98

= 43/49

Answer.