Question

An integer is chosen at random between 1to100thenprobability that it is


divisible by 8 and not divisible by 8
​

Answer 1

Step-by-step explanation:

Total integers divisible by 8 are 12 and total integers not divisible by 8 are 88(100-12=88)

Probability of getting an integer divisible by 8=12/100=3/25

Also, probability of getting an integer not divisible by 8 = 88/100= 22/25

...hope it will help✌...

Answer 2

Answer:

Sample space (S) = {2, 3, 4 ...... 98, 99}

n(S) = 98

(i) An integer is divisible by 8  

E = {8, 16, 24, 32 ...... 96}

n(E) = 12

n = 96-8/8+1

Probability of chosen a number divisible by 8

P(E) = n(E)/n(S)

= 12/98

= 6/49

Probability of chosen a number divisible by 8

= 6/49

(ii) Probability of chosen a number is not divisible by 8 = P (bar E)

p (bar E) 1- p(E)

1-6/49 = 49-6/49

Probability of chosen a number is not divisible by 8 = 43/49.r E) = 43/49