Question

an integer is chosen at random
from 10-90. find probability of
getting number divisible by 6...?

Answer 1

p(divisible by 6) = total number divisible by 6 in range / total number in range

total number in range= 90-10+1= 81

first number in range divisible by 6 is 12 and last is 90.

lets find out total number divisible by 6

12, 18, 24. . . . 90

lets find it by ap

last term is Tn = 90

first term is a =12

common difference d = 6

Tn = a + (n-1)d

90 = 12 +(n-1)6

6n +6 =90

n = 84/6

n = 14

so total number divisible by 6 in rane is 14.

now

p(divisible by 6) = 14/81

please .mark it brainliest if it helps

Answer 2

Total outcomes=90

Probability=Favourable outcomes
-------------------------------
Total outcomes

Favourable outcomes=12,18,24,30,36,42,48,54,60,66,72,78,84,90

==>P(divisible by 6)=14/90
=7/45 Answer