an integer is chosen at random
from 10-90. find probability of
getting number divisible by 6...?
Answers
Answered by
1
p(divisible by 6) = total number divisible by 6 in range / total number in range
total number in range= 90-10+1= 81
first number in range divisible by 6 is 12 and last is 90.
lets find out total number divisible by 6
12, 18, 24. . . . 90
lets find it by ap
last term is Tn = 90
first term is a =12
common difference d = 6
Tn = a + (n-1)d
90 = 12 +(n-1)6
6n +6 =90
n = 84/6
n = 14
so total number divisible by 6 in rane is 14.
now
p(divisible by 6) = 14/81
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+1 kyu kiya..?
+1 tab karte hai jab between likha ho, but is question main toh from likha hai isliye total outcomes 90 hi rahengi
and it is a question from probability not from AP
Question me mention hai ki from 10 to 90 any 1 number is picked randomly so if you will count you will find total of 81 numbers. Also to find total number divisible by 6 in the given range i used Ap, we should use Ap because this range can be very large so this is the good approach to find total count.
from ka matlab hota hai से and in this question 10-90 is 90
jaise hum kethe hai 2 से 5 toh kitne number hue 3
+1 to include number 10 too. This is general formula to find total number between a given consecutive series of natural number
range = end - start + 1
for example from 10 - 20
range = end - start + 1
for example from 10 - 20
from 10-20 => 20-10+1 = 11
from 1- 50 => 50-1+1 = 50
from 1- 50 => 50-1+1 = 50
ok
Answered by
0
Total outcomes=90
Probability=Favourable outcomes
-------------------------------
Total outcomes
Favourable outcomes=12,18,24,30,36,42,48,54,60,66,72,78,84,90
==>P(divisible by 6)=14/90
=7/45 Answer
Probability=Favourable outcomes
-------------------------------
Total outcomes
Favourable outcomes=12,18,24,30,36,42,48,54,60,66,72,78,84,90
==>P(divisible by 6)=14/90
=7/45 Answer
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