an integer is chosen at random
from 10-90. find probability of
getting number divisible by 6...?
Answers
Answered by
1
p(divisible by 6) = total number divisible by 6 in range / total number in range
total number in range= 90-10+1= 81
first number in range divisible by 6 is 12 and last is 90.
lets find out total number divisible by 6
12, 18, 24. . . . 90
lets find it by ap
last term is Tn = 90
first term is a =12
common difference d = 6
Tn = a + (n-1)d
90 = 12 +(n-1)6
6n +6 =90
n = 84/6
n = 14
so total number divisible by 6 in rane is 14.
now
p(divisible by 6) = 14/81
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+1 kyu kiya..?
range = end - start + 1
for example from 10 - 20
from 1- 50 => 50-1+1 = 50
Answered by
0
Total outcomes=90
Probability=Favourable outcomes
-------------------------------
Total outcomes
Favourable outcomes=12,18,24,30,36,42,48,54,60,66,72,78,84,90
==>P(divisible by 6)=14/90
=7/45 Answer
Probability=Favourable outcomes
-------------------------------
Total outcomes
Favourable outcomes=12,18,24,30,36,42,48,54,60,66,72,78,84,90
==>P(divisible by 6)=14/90
=7/45 Answer
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