An integer is chosen at random from first two hundred natural numbers. what is the probability that the integer chosen is divisible by 6 or 8?
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Answered by
6
Total no of Outcomes= 200
No.of digit that is divisible by 6= 33
No of digit divisible by 8= 25
so, Total no. of favourable outcomes= 33+25= 58
=> P(divisible by 6 or 8) = 58/200..
No.of digit that is divisible by 6= 33
No of digit divisible by 8= 25
so, Total no. of favourable outcomes= 33+25= 58
=> P(divisible by 6 or 8) = 58/200..
Answered by
1
Total Numbers which are divisible by 6 = 16
Total numbers divisible by 8 = 12
Total of these = 28
Therefore probability is = 28/100 = 7/25(Ans)
Total numbers divisible by 8 = 12
Total of these = 28
Therefore probability is = 28/100 = 7/25(Ans)
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