Question

An integer is chosen at random from the number ranging from 1 to 50.what is the probability that the integer chosen is a multiple of 2 or 3 or 10

Answer 1

Answer: There is probability of $\dfrac{16}{25}$ for choosing a multiple of 2 or 3 or 10.

Step-by-step explanation:

Since we have given that

Number written ranging from 1 to 50.

We need to find the integer chosen is a multiple of 2 or 3 or 10.

So, Possible outcomes are

{2,3.4,6,8,9,10,12,14,15,16,18,20,21,22,24,26,27,28,30,32,33,34,36,38,40,42,44,45,46,48,50}

Number of favourable outcomes = 32

So, probability that the integer chosen is a multiple of 2 or 3 or 10 is given by

$\dfrac{32}{50}=\dfrac{16}{25}$

Hence, there is probability of $\dfrac{16}{25}$ for choosing a multiple of 2 or 3 or 10.

Answer 2

Answer:

Hi ! Your answer will be 33/50

Step-by-step explanation:

Event=

(2,3,4,6,9,10,12,14,15,16,18,21,22,24,27,28,30,32,33,34,36,38,39,40,42,45,46,48,50)

n(S)=50

n(E)=33

Therefore, P(E)=n(E)/n(S)=33/50

Hope you find it helpful.