An integer is chosen at randon between 1 and 100 . Find probablity it is divisible by8
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An integer is chosen between 1 and 100.
Numbers that are divisible by 8 = 8, 16, 24, 32, 40, 48, 56, 64, 72, 80, 88 and 96.
The rest are not divisible by 8.
Calculation:
The integers are 2, 3, 4, 5, 6,..., 99.
The number of possible outcomes = 98 (Excluding 1 and 100)
Therefore,
Sample space, n(S) = 98.
So,
The possibility of the number divisible by 8, n(E) = 12.
To find probability,
By formula,
P(E) = n(E)/n(S)
=12/98
= 6/49
Hence, P(integer divisible by 8) = 6/49
To find the possibility of the number not divisible by 8,
Probability of an integer it is not divisible by 8,
By formula,
P(E') = 1 - P(E)
1 - 6/49 = (49 - 6)/49
Hence, P(integer not divisible by 8) = 43/49
Numbers that are divisible by 8 = 8, 16, 24, 32, 40, 48, 56, 64, 72, 80, 88 and 96.
The rest are not divisible by 8.
Calculation:
The integers are 2, 3, 4, 5, 6,..., 99.
The number of possible outcomes = 98 (Excluding 1 and 100)
Therefore,
Sample space, n(S) = 98.
So,
The possibility of the number divisible by 8, n(E) = 12.
To find probability,
By formula,
P(E) = n(E)/n(S)
=12/98
= 6/49
Hence, P(integer divisible by 8) = 6/49
To find the possibility of the number not divisible by 8,
Probability of an integer it is not divisible by 8,
By formula,
P(E') = 1 - P(E)
1 - 6/49 = (49 - 6)/49
Hence, P(integer not divisible by 8) = 43/49
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