Question

An integer is chosen between 0 to 50. What is
the probability that it is divisible by 4?​

Answer 1

4,8,12,16,20,24,28,32,36,40,44,48

12 Numbers

So

$\frac{12}{50} = \frac{6}{25}$

Answer 2

Given:

An integer is chosen between 0 to 50.

Solution:

Number of integers between 0 and 50 = 49

Number of possible outcomes =49

Assume that E is the event of getting an integer divisible by 4.

Total favorable outcomes are 4, 8, 12, 16, 20, 24, 28, 32, 36, 36, 44, and 48

Number of total favorable outcomes = 12

Therefore the probability that it is divisible by 4 is,​

$\[{\rm{P(E)}} = \frac{{{\rm{Number}}\,{\rm{of}}\,{\rm{favourable}}\,{\rm{outcomes}}}}{{{\rm{Number}}\,{\rm{of}}\,{\rm{possible}}\,{\rm{outcomes}}}}\]$

         $=\[\frac{{12}}{{49}}\]$

Hence, the probability that it is divisible by 4 is $\[\frac{{12}}{{49}}\]$.