Question

an integer is chosen between 70 and hundred find the probability of getting a prime number and a no divisible by seven​

Answer 1

Answer:

Probability of getting a prime number is 6/29.

Probability of a no to be divisible by seven is 4/29.

Step-by-step explanation:

Total no. of integers that are to be chosen between 70 & 100 = 29

Case 1: Probability of getting a prime number

Let the event of choosing a number which is a prime number be “E1”.

Prime numbers between 70 & 100 are as follows: [71, 73, 79, 83, 89, 97]

So, total no. of favourable events = 6

∴ Probability of getting a prime number,

P(E1) = 6/29

Case 2: Probability of getting a number which is divisible by seven

Let the event of choosing a number which divisible by 7 be “E2”.

Numbers between 70 & 100 which are divisible by 7 are as follows: [77, 84, 91, 98]  

So, total no. of favourable events = 4

∴ Probability of getting a number which is divisible by 7,

P(E2) = 4/29

Answer 2

Answer:

Step-by-step explanation:

total no. of integers b/w 70 and 100 are 29.

then, n(s)=29

Case 1

total no. of prime no.s - 6 (71, 73, 79, 83, 89, 97)

n(E1) = 6

p(E of getting a prime no.) = 6/29

case 2

total no. of integers divisible by 7 - 4 (77, 84, 91, 98)

n(E2) = 4

p(E of getting a no divisible by 7) = 4/29

   

Hope it was helpful!!