Question

An integer is chosen from 1 and 99, What is the probability that it is:
(i) divisible by 3 and 5
(ii) not divisible by 3 and 5
(iii) a perfect square
(iv) prime number​

Answer 1

(i) 0.06

(b) 0.94

(c) 0.08

(d)0.24

Step-by-step explanation:

We have given the integers from 1 to 99

Total numbers from 1 to 99 = 100

(A) The number which is divisible by 3 and 5 are 15,30,45,60,75,90 = 6

So probability will be $=\frac{6}{100}=0.06$

(b) The number which are not divisible by 3 and 5 are 100-6 = 94

So probability will be $=\frac{94}{100}=0.94$

(c) A perfect square = 4,9,16,25,36,49,64,81

So total number = 8

So probability will be $=\frac{8}{100}=0.08$

(d) Prime number between 1 and 99 are

2,3,5,7,11,13,17,19,23,29,31,37,41,43,47,53,61,67,71,73,79,83,89,97 = 24

So probability will be $\frac{24}{100}=0.24$

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