Question

an integer is chosen from first 200 digit. what is the probability of the integer that is chosen will be a multiple of 6 or 8

Answer 1

Probability is 1 / 4

Step-by-step explanation:

Sample Space:

Integers that are divisible by 6:

6,12,18,24,30,36,42,48,54,60,66,72,78,84,90,96,102,108,114,120,126,132,138,144,150,156,162,168,174,180,186,192,198.

Integers that are divisible by 8:

8,16,24,32,40,48,56,64,72,80,88,96,104,112.120,128,136,144,152,160,168,176,184,192,200.

Integers which are divisible by 6 only

= 200 / 6

= 33 2/6

Take round off value 33

Integers which are divisible by 8 only

= 200 / 8

= 25

LCM. Of 6 & 8 = 24 (numbers divisible by both 6 & 8)

Integers divisible by 24

200 / 24

= 8 8/24

Take round off = 8

Now p(E) = (33 + 25 - 8) / 200

= 50 / 200

= 1 / 4