An integer is such that twice of its square is 7 less than the 9 multiple of that integer. Integer is
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2x^2 = 9x - 7
=> 2x^2 - 9x + 7 = 0
=> 2x^2 - 2x - 7x + 7 = 0
=> 2x(x -1) -7( x-1) =0
=> (x-1) (2x-7) =0
=> x = 1, 7/2
=> 2x^2 - 9x + 7 = 0
=> 2x^2 - 2x - 7x + 7 = 0
=> 2x(x -1) -7( x-1) =0
=> (x-1) (2x-7) =0
=> x = 1, 7/2
shameemamk:
Answer is only 1 as it is given that the number is an integer
yeah
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