Question

An integer when divided 9 gives a remainder 2. The resulting quotient when divided by 4 gives a remainder 1. The resulting quotient is then divided by 9 giving a quotient 1 and a remainder 6. What will be the final remainder , if the order of the divisors is reversed?

Answer 1

Step-by-step explanation:

Dividend 1 = 9*1+6 = 15

Dividend 2 = 15*4 + 1 = 61

Dividend 3 =61*9 + 2 = 551

ab divisiors reversed ho gye

551/9 = 61 and 2 rem.

61/4 = 15 and 1 rem

15/9 = 1

final remainder = 6 (Ans).

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