Math, asked by ratnakumari9999, 4 months ago


An
integer when divided by
-3 given quotient 15
15 and
leaves
remainder 2,​

Answers

Answered by savita247854
1

Answer:

On subtracting 5 from each number:

16 − 5 = 11

36 − 5 = 31

40 − 5 = 35

The required number will be the least common multiple of 11, 31 and 35.

L.C.M. of 11, 31 and 35 = 11×31×35

= 11935

This is because they do not have any factor in common.

So, 11935 is the required number.

WhatsApp_icon

fb_icon

500000+ Question Answers

Similar Questions

ques_icon

18) TallymarksillイⅢ l show A) 9 B) 10 C) 11 D) 12 19) 227+25 A) Quotient-9, Remainder-2 C) Quotient-11, Remainder-2 B) Quotient=5, Remainder=7 D) Quotient-4, Remainder-2. ...

ques_icon

7. A positive integer n when divided by 9, gives 7 as remainder. What will be the remainder when 3n - 1 is divided by 9? ...

ques_icon

en 15. Using remainder theorem, find the value of k if on dividing 23 +3x2 - lr 5 by x - 2, 12016] leaves a remainder 7 ...

ques_icon

Q4. Find the largest number that will divide 398,436 and 542 leaving remainder 7, 11 and 15 i each case ...

ques_icon

Find the least number which when divided by 35, 56 and 91 leaves the same remainder 7 in each case. ...

ques_icon

10. Find the least number which when divided by 35, 56 and 91 leaves the same remainder 7 in each case. ...

ques_icon

4. Find the least number which when divided by 12, 16, 24 and 36 leaves a remainder 7 in each case. ...

ques_icon

When a polynomial f(x) is divided by (x - 1), the remainder is 5 and when it is divide by (r -2), the remainder is 7. Find the remainder when it is divided by (x-1) (2) ...

ques_icon

b Telltainders U. Find the least number which when divided by 35, 56 and 91 leavest same remainder 7 in each case. 11 Tiu ...

Answered by sumanthbhat99
1

Step-by-step explanation:

x=(-3)(15)+2

x= -45+2

x= -43

Similar questions