An integer when divied by 6 gives a remainder 4. the resulting quotient when divided by 7 gives a remainder 6. The resulting quotient is then divided by 6 giving a quotient I and a remainder 3. What will be the final remainder, if the order of the divisons esreversed ?
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3 will be the final remainder--
Let say Integer = P
P = 6Q + 4
Q = 7R + 6
R = 6 * 1 + 3
=> R = 9
Q = 7*9 + 6
=> Q = 69
P = 6*69 + 4
=> P = 414 + 4
=> P = 418
Integer = 418
418/6 = 69* 6 + 4
69/7 = 9* 7 + 6
9/6 = 1 * 6 + 3
Remainder = 3
I hope it helps
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