Question

An inverted bell lying at the bottom of a lake 47.6m deep has 50cm3 of air trapped of it .the bell is brought to the surface of the lake. The volume of the trapped air will (atmosphere pressure=70 cm of Hg and dwnsity of Hg is 13.6 gm per cm cubr

Answer 1

Answer:

Correct option is

Correct option isA

Correct option isA  300 cm3 

Correct option isA  300 cm3 According to Boyle's law PαV1

Correct option isA  300 cm3 According to Boyle's law PαV1We know that,

Correct option isA  300 cm3 According to Boyle's law PαV1We know that,V2=(1+P0hρωg)V1V2=(1+70×13.6×100047.6×102×1×1000)V1V2=(1+5)50cm3=300cm3

Correct option isA  300 cm3 According to Boyle's law PαV1We know that,V2=(1+P0hρωg)V1V2=(1+70×13.6×100047.6×102×1×1000)V1V2=(1+5)50cm3=300cm3[P0=P2=70cmofHg=70×13.6×1000]