Question

an inverted cone of height 10 cm and base radius 6.4 cm contains water to a depth of 5 cm, measured from the vertex. calculate the volume of water in the cone

Answer 1

Answer:

r of big cone =6.4cm

h=10cm

Depth of water in that cone =5cm

Acc. To statement they must be similar triangles.

Because{ h of big cone }/depth of water =2/1

So r/R=2/1

So ,R of small cone =3.2cm

We have to find the vol. Of small cone i.e.

==== 1/3 πr^2h

=1/3 ×22/7×3.2 ×3.2 ×5

=1/3×22/7×51.2

=1126.4/21

=53.638cm^3

So, vol. Of water left in cone =53.63cm^3