Question

an inverted v is made up of two uniform boards joint and each weighing 200N.each side has the same length and make an angle of 30 degree with the vertical. the magnitude of statics frictional force that acts on each of the lower end of the v is. ​

Answer 1

Answer:

the magnitude of statics frictional force that acts on each of the lower end of the v is 57.7 N

Explanation:

By force balance in vertical direction we have

$2F_n = mg + mg$

$F_n = mg$

$F_n = 200 N$

now by torque balance about the top junction of two rods

Torque due to normal force = torque due to weight + Torque due to friction force

so we will have

$F_n(Lsin30) = Mg(\frac{L}{2}sin30 + F_f(Lcos30)$

now we have

$200 sin30 = 100 sin30 + F_f cos30$

$100 - 50 = F_f cos30$

$F_f = 57.7 N$

#Learn

Topic : Torque Balance

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