Question

An investor has ₹ 7100 of these, he invested partly in 6% at 96 and remaining in 8% at 104. If the income from both the stock, taken together is ₹500. Find the amount he invested in each of the stock.

Answer 1

Given :  An investor had ₹ 7100. Of these,

he invested partly in 6% at 96 and

the remaining in 8% at  104.

Income from both the stocks, taken together is ₹ 500,

To Find : Amount he invested  in each of the stocks.​

Solution:

Amount Invested   in 6% at 96    = x  Rs

and Amount Invested  8% at  104  = 7100 - x  Rs

Stocks bought of 6% at 96    =  x/96

Income = (x/96)  * 6    =   x/16   Rs

Stocks bought of 8% at 104  =  (7100-x)/104

Income =((7100-x)/104)  * 8    =(7100-  x)/13   Rs

x/16  + (7100-  x)/13   = 500

=>  13x  + 16(7100 - x)  = 104000

=> -3x + 1,13,600 = 104000

=> 3x = 9600

=> x = 3200

7100 - x  = 3900  

Hence Invested in each stock  = 3200 and 3900  Rs

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Answer 2

Step-by-step explanation:

Amount Invested in 6% at 96 = x

Rs and Amount Invested 8% at 104 = 7100 - x

Rs

Stocks bought of 6% at Income = (x/96) * 6 = 96 = x / 96 x/16 Rs

Stocks bought of 8% at 104 = (7100-x)/104 Income =((7100-x)/104) * 8 (7100- x)/13 Rs

x / 16 + (7100 - x) / 13 = 500

=> 13x + 16(7100-x) = 104000

=> -3x + 1,13,600 = 104000

=> 3x = 9600

=> x= 3200

7100 - x = 3900

Hence Invested in each stock = 3200 and 3900 Rs.