Physics, asked by tawadeaditi28091998, 10 months ago

an ion charge 5 ×10 power 7 C/ kg enters in transverse magnetic field of intensity 4 × 10 power -2 Teska with velocity of 2 × 10 power 5 m/ sec. Radius of its circular oath will be ?​

Answers

Answered by crbedutech
1

The radius of circle = 0.1 m

Explanation:

When a charged particle moves in the magnetic field , the centripetal force acts upon it . Which make it to move in a circle . The relation

The force  due to magnetic field   Bqv = mv²/r    

or r = mv/Bq = 1 Х 2 Х 10⁵/4Х 10⁻²Х5Х10⁷ = 1/10 = 0.1 m

Similar questions