an ion charge 5 ×10 power 7 C/ kg enters in transverse magnetic field of intensity 4 × 10 power -2 Teska with velocity of 2 × 10 power 5 m/ sec. Radius of its circular oath will be ?
Answers
Answered by
1
The radius of circle = 0.1 m
Explanation:
When a charged particle moves in the magnetic field , the centripetal force acts upon it . Which make it to move in a circle . The relation
The force due to magnetic field Bqv = mv²/r
or r = mv/Bq = 1 Х 2 Х 10⁵/4Х 10⁻²Х5Х10⁷ = 1/10 = 0.1 m
Similar questions