Question

An ion has 14 neutrons, 10 electrons, and a mass number of 27.

Answer 1

that will be Al^+3...

Answer 2

Given:

Number of electrons in ion = 10

Number of neutrons in ion = 14

Mass number of element = 27

To find:

Name of the ion

Solution:

• According to the mass number given, the element is identified as Aluminium.

• To confirm the number of neutrons given, when the difference between the mass number (27) atomic number (13) is found it gives 14.
• Thus the given ion belongs to Aluminium atom.
• Atomic mass of any element is equal to the number of the protons which is in turn equal to the number of electrons.
• In this case, the number of electrons is given as 10, which means that the ion has donated the electron.
• As it has donated 3 electrons, and it is the ion of aluminium, the ion is identified as $Al^{3-}$.

Conclusion:

Thus the ion with 14 neutrons, 10 electrons, and a mass number of 27 is identified as $Al^{3-}$.

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