Question

An ion of Fe (atomic no. 26) is found to have
magnetic moment as 35 B.M. Give the
magnitude of positive charge on ion in units of
charge of an electron.​

Answer 1

the above is your answer

Answer 2

Answer:

Explanation:

Magnetic moment, also understood as magnetic dipole moment, exists as the measure of the object's tendency to align with a magnetic field. “Magnetic Moment is described as magnetic strength and direction of a magnet or other object that produces a magnetic field.” The magnetic moment exists as a vector quantity.

A vector quantity is a measure of the torque exercised on a magnetic system (such as a bar magnet or dipole) when positioned in a magnetic field and for a magnet exists the product of the distance between its poles and the strength of either pole.

Since Magnetic moment $=\sqrt{n(n+2)}$

$=4.9$

Therefore,$n=4$ (where n is no. of the unpaired electron)

Thus $M n^{a+}$ ion has four unpaired electron

$&25 M n^{3+}: 1 S^{2}, 2 S^{2} 2 P^{6}, 3 S^{2}, &3 P^{6} 3 d^{4}$

Therefore, a=3

The magnitude of positive charge on ion in units of charge of an electron is a=3.

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