Question

An ion with mass number 37 possess one unit of negative charge. if the ion contains 11.1% more neutrons than electrons, find the symbol to this ion.

Answer 1

Adarsha pandu this question is wrong please check..

Answer 2

$\fbox\textcolor{orange}{\texttt{Answer = Cl(37,17)}}$

$\textcolor{indigo}{\texttt{Explanation :-}}$

Suppose no. of electrons = x

no. of neutrons = $x + \frac{11.1}{100}\times{x}\: = \:1.111x$

No. of electrons in the neutral atom = $x - 1$

No. of protons in the neutral atom =$x - 1$

Mass no. = no. of neutrons + no. of protons

ie, $37\:=\:1.111x+x-1$

$2.111x\:=\:37+1\:=\:38$

$x = \frac{38}{2.111}\:=\texttt{18}$

No. of protons = Atomic no. =

$x-1\:=\:18-1\:=\texttt{17}$

Hence the symbol of the ion is: $</h3><h3>\fbox{^{37}_{17}Cl}$