Question

An ion with mass number 56 contains 3 unit of positive charge and 30.4% more neutrons than electrons find the symobol of ion

Answer 1

Let the number of electrons in ion = x
Number of neutrons = x+0.304x = 1.304x
Number of electrons in neutral atom = x+3
Number of protons in neutral atom = x+3
Mass number = 56
(x+3)+(1.304x)=56
X = 23
Number of protons = x+3 = 26
Symbol of ions = Fe3+

Answer 2

Answer: The symbol of the ion is $Fe^{3+}$

Explanation:

We are given:

Atomic mass of the element = 56

Let us assume that the number of electrons in the given element is 'x'

So, number of neutrons = 30.4 % more than the electrons

Number of neutrons = $x+0.304x=1.304x$

It is also given, that number of electrons in neutral atom = x + 3

In a neutral atom, number of electrons is always equal to number of protons

Number of protons = x + 3

Atomic mass is the sum of number of protons and number of neutrons present in an atom.

According to question:

$(x+3)+(1.304x)=56\\x=23$

Number of protons = (23 + 3) = 26

So, the element having atomic number as 26 is Iron having symbol ' Fe' and this element carries a charge of +3 units.

Hence, the symbol of the ion is $Fe^{3+}$