Chemistry, asked by kirti1999, 1 year ago

An ionic bond A+B- is most likely to be formed when :
(1) The ionizationenergy of A is high and the electron affinity of B is low
(2) The ionizationenergy of A is low and the electron affinity of B is high
(3) The ionization energy of A and the electron affinity of B is high
(4) The ionization energy of A and the electron affinity of B is low

Answers

Answered by itemderby
28

Answer: Option (2) is the correct answer.

Explanation:

Ionization energy is defined as the energy necessary to remove an electron from a gaseous atom or ion.

So, an atom with low ionization means that only amount of energy is required by an atom to lose its loosely bound valence electron.

On the other hand, electron affinity is defined as the energy absorbed when an electron is added to an atom or molecule in the gaseous state.

So, an atom with high electron affinity means it will readily accept an electron from another atom.

Hence, we can conclude that an ionic bond A^{+}B^{-} is most likely to be formed when the ionizationenergy of A is low and the electron affinity of B is high.

Answered by bhavya29007
0

Explanation:(2) The ionizationenergy of A is low and the electron affinity of B is high

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