Question

An ionic solid a+b crystallises as a fcc structure. If the edge length of cell is 508 pm and radius of anion is 144 pm, the radius of cation is :

Answer 1

Answer:-

Edge length = a = 508pm

Radius of anion = 144pm (r-)

Radius of cation = ? (r+)

Using formula a = r+/r- , we get:-

508 pm = r+/144 pm

r+ = 508×144 = 73,152 pm

or, r+ = 7.31 cm