Question

An ionic solid consists of two elements ‘X’ and ‘Y’. The X- anions form the FCC arrangement and Y+

ions occupy

all the octahedral voids and alternate tetrahedral voids. What is the simplest formula of the compound?​

Answer 1

Answer:

ANSWER

No of atoms in a CCP unit cell=similar to FCC=4

Therefore no of B atoms present=4

No of A atom=tetrahedral void and octohedral void(4+2)=6

The formula of the compound = A

3

B

2