An ionic solid, xy has bcc structure with edge length equal to 4.4 . The minimum distance between two oppositely charged ions is
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Answer:
The minimum distance between them is √3×4.4÷2=3.8105
Explanation:
BCC stands for body- centered- cubic arrangement as the name suggest in BCC atoms are placed at the corner of the cube and also in its body centered position.
The distance between the corner of a cube and its body-centered position is given by √3×a÷2
Where a is the edge length of the cube.
In Ionic solid xy , positive set of ions occupy all the eight corners of the cube and the negative charged ion is placed at its center, therefore the minimum distance between them is √3×4.4÷2=3.8105
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