Question

An ionic solid, xy has bcc structure with edge length equal to 4.4 . The minimum distance between two oppositely charged ions is

Answer 1

Answer:

The minimum distance between them is √3×4.4÷2=3.8105

Explanation:

BCC stands for body- centered- cubic arrangement as the name suggest in BCC atoms are placed at the corner of the cube and also in its body centered position.

 The distance between the corner of a cube and its body-centered position is given by √3×a÷2

Where a is the edge length of the cube.

In Ionic solid xy , positive set of ions occupy all the eight corners of the cube and the negative charged ion is placed at its center, therefore the minimum distance between them is √3×4.4÷2=3.8105