Question

An IP packet with 2500 bytes of data (plus header) passes through an IP network with MTU = 500 bytes. How many additional bytes will be delivered at the destination?

Answer 1

Answer:

An IP router with a Maximum Transmission Unit (MTU) of 1500 bytes has received an IP packet of size 4404 bytes with an IP

Answer 2

Answer:

b. 100

Explanation:

Header + Data = 2500 bytes

We know Header size is 20 bytes for IP Packet. So, Data = 2500 - 20 =>2480 bytes

MTU = 500, Similarly 20 bytes for Header and 480 bytes for Data.

2480 / 480 = 5.16666667 => approximately 6 fragments.

6 * 20 = 120 bytes data of delivered as a Header at the destination.

So, (2480 + 120) - 2500 = 100 bytes.