Question

An IP packet with 2500 bytes of data (plus header) passes through an IP network with MTU = 500 bytes. How many additional bytes will be delivered at the destination?

a. 64

b. 100

c. 150

d. 200

Answer 1

Answer:

An IP router with a Maximum Transmission Unit (MTU) of 1500 bytes has received an IP packet of size 4404 bytes with an IP

Answer 2

Answer:

100

Explanation:

Generally, IP header= 20 bytes

So,

Data to be transmitted = 2500 - 20 = 2480 bytes

Since we have MTU = 500,

Fragmentation will occur.

So,

Size of data that can be transferred in 1 fragment = 500 - 20 = 480 bytes

No. of fragments = 2480 / 480 = 5.1666667 . Say 5.

Now, Each fragments has the IP header of 20 bytes, which is the extra byte.

So, 5*20 = 100 bytes.