An iron anchor weighs 250 pounds in air and has a weight density of 480 lbs/ft3. If it is immersed in sea water that has a weight density of 64 lbs/ft3, how much force would be required to lift it while it is immersed?
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Answer:
Given:
weight of anchor = W = 250 pounds
weight of density p= 480lbs / ft³
weight of anchor= 250/ 480 = 0.520 ft³
density of sea water p⁸= 64lbs/ ft³
buoyant force on anchor when immersed in sea water = p⁸×v = 33.28 lbs
Force required to lift the anchor=Weight-Buoyancy
F= 250 -33.28= 216.72 lbs
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