An iron ball having a mass of 28 g is added to a graduated cylinder containing 45 ml of water. The water level rises to 49 ml mark. From this information, calculate the density of iron in CGS and SI unit.
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Answers
Answer:
Given,
Mass of iron ball = 28g
Volume 1 of iron ball = 45ml
Volume 2 of iron ball = 49ml
Density of iron ball = ?
Volume of iron ball = V1-V2
= 49-45
=4ml ( 1 ml = 1 cm3)
=4 cm3
Density of iron ball in g/cm3 = mass/volume
=28/7
=7g/cm3
1g/cm3 = 1000 kg/m3
7g/cm3 = 7*1000
=7000 kg/m3
Density of iron ball in kg/m3 = 7000 kg/m3
Explanation:
Given : An iron ball having a mass of 28 g is added to a graduated cylinder containing 45 ml of water. The water level rises to 49 ml mark.
To Find : density of iron in CGS and SI unit.
Solution:
Water level raised because of iron ball = 49 - 45 = 4 ml
Hence Volume of iron ball = 4ml = 4 cm³
mass of iron ball = 28 g
Density = mass / volume
=> density = 28 / 4 = 7 g/cm³
Density in CGS unit = 7 g/cm³
1 g = 1 kg /1000
1 cm = 1 m /100 => 1 cm³ = 1 m³ /100³
Hence Density in SI unit = (7/1000) /( 1/ 100³)
= 7000 kg/m³
Density in SI unit = 7000 kg/m³
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