An iron ball having a mass of 28 g is added to a graduated cylinder containing 45 ml of water. The water level rises to 49 ml mark. From this information, calculate the density of iron in CGS and SI unit.
step to step answer
Answers
Given : An iron ball having a mass of 28 g is added to a graduated cylinder containing 45 ml of water. The water level rises to 49 ml mark.
To Find : density of iron in CGS and SI unit.
Solution:
Water level raised because of iron ball = 49 - 45 = 4 ml
Hence Volume of iron ball = 4ml = 4 cm³
mass of iron ball = 28 g
Density = mass / volume
=> density = 28 / 4 = 7 g/cm³
Density in CGS unit = 7 g/cm³
1 g = 1 kg /1000
1 cm = 1 m /100 => 1 cm³ = 1 m³ /100³
Hence Density in SI unit = (7/1000) /( 1/ 100³)
= 7000 kg/m³
Density in SI unit = 7000 kg/m³
Learn More:
The relative density
https://brainly.in/question/11755561
The mass per unit volume of a
https://brainly.in/question/4271718
Answer:
Given : An iron ball having a mass of 28 g is added to a graduated cylinder containing 45 ml of water. The water level rises to 49 ml mark.
To Find : density of iron in CGS and SI unit.
Solution:
Water level raised because of iron ball = 49 - 45 = 4 ml
Hence Volume of iron ball = 4ml = 4 cm³
mass of iron ball = 28 g
Density = mass / volume
=> density = 28 / 4 = 7 g/cm³
Density in CGS unit = 7 g/cm³
1 g = 1 kg /1000
1 cm = 1 m /100 => 1 cm³ = 1 m³ /100³
Hence Density in SI unit = (7/1000) /( 1/ 100³)
= 7000 kg/m³
Density in SI unit = 7000 kg/m³
Hope it helps you !!
Pls mark me brainlist !!